(;AP[Hexon:0.0]FF[4]GM[11]SZ[11]C[2022/08/19

Black\: Jia
White\: Scott

Handicap\: 0

White wins.]PL[B]
;B[c4]
;W[f6]C[Peter\: White chose not to swap, although swapping would have been a good idea.]
;B[e7]
;W[e6]
;B[d6]
;W[d7]
;B[b8]
;W[c9]
;B[a10]
;W[a11]
;B[b10]
;W[b11]
;B[c10]
;W[c11]
;B[d10]
;W[d11]
;B[g9]
;W[f10]
(;B[f9]C[Peter\: Better h8, see next variation.]
 ;W[g10]
 ;B[i9]C[Eric\: Black should first get e10, in case it matters later.

https\://www.hexwiki.net/index.php/Peep]
 ;W[h9]
 ;B[i8]
 ;W[h8]
 ;B[j6]
 ;W[j5]
 (;B[g7]C[Peter\: Blunder, as White i6 is now immediately winning. The next two variations were also played.]
  ;W[i6]
  ;B[resign])
 (;B[h7]C[Peter\: Also a blunder.]
  ;W[i7])
 (;B[i6]C[Peter\: Better.]
  ;W[g7]
  ;B[h5]
  (;W[h1]C[Peter\: Better i5 followed by h4, see next variation.

Now Black has many ways of connecting. Perhaps the simplest is i3 leading to a 2nd row ladder. See 2nd variation on the next move.

Eric\: What about H2 instead of H4?]
   (;B[g4]
    ;W[f1]
    (;B[c3]C[Peter\: Much faster\: h2 followed by a bicycle template. See next variation.

The following sequence of moves is a muddle, and it is difficult to see exactly at which point Black loses the win. (It is with move 39).]
     ;W[f4]
     ;B[h3]
     ;W[i2]
     ;B[g3]
     ;W[e3]
     (;B[g1]C[Peter\: Losing move. f2 was still winning. See next variation.]
      ;W[g2]
      ;B[f3]
      ;W[f2]
      ;B[e4]
      ;W[d4]
      ;B[c5]
      ;W[d5]
      ;B[e5]
      ;W[c6]
      ;B[j2]
      ;W[i3]
      ;B[resign])
     (;B[f2]
      ;W[g1]
      ;B[e2]))
    (;B[h2]
     ;W[i1]
     ;B[j2]))
   (;B[i3]
    ;W[j1]
    ;B[h2]
    ;W[i1]
    ;B[g2]
    ;W[g1]
    ;B[e3]
    ;W[e2]
    ;B[c3]))
  (;W[i5]C[Peter\: This seems like a better try, but doesn't work either.]
   ;B[h6]
   (;W[h4]
    ;B[g5]
    ;W[g4]
    ;B[f5]
    ;W[f3]
    ;B[f4]
    ;W[g3]
    ;B[d5])
   (;W[h2]C[Eric\: What about this? (my move  ^_^ ).

Peter\: Interesting idea, and locally better, but doesn't work here. See next moves.
]
    ;B[g4]
    ;W[f3]
    ;B[e5]
    ;W[d4]
    ;B[c5]))))
(;B[h8]
 ;W[f9]
 ;B[g7]
 ;W[e8]
 ;B[h5]))
